1/(2m^2)=(1/m)-(1/2)

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Solution for 1/(2m^2)=(1/m)-(1/2) equation: 


D( m )

m = 0

2*m^2 = 0

m = 0

m = 0

2*m^2 = 0

2*m^2 = 0

2*m^2 = 0 // : 2

m^2 = 0

m = 0

m in (-oo:0) U (0:+oo)

1/(2*m^2) = 1/m-(1/2) // - 1/m-(1/2)

1/(2*m^2)-(1/m)+1/2 = 0

1/(2*m^2)-m^-1+1/2 = 0

1/2*m^-2-m^-1+1/2 = 0

t_1 = m^-1

1/2*t_1^2-1*t_1^1+1/2 = 0

1/2*t_1^2-t_1+1/2 = 0

DELTA = (-1)^2-(1/2*1/2*4)

DELTA = 0

t_1 = 1/(1/2*2)

t_1 = 1 or t_1 = 1

t_1 = 1

m^-1-1 = 0

1*m^-1 = 1 // : 1

m^-1 = 1

-1 < 0

1/(m^1) = 1 // * m^1

1 = 1*m^1 // : 1

1 = m^1

m = 1

t_1 = 1

m^-1-1 = 0

1*m^-1 = 1 // : 1

m^-1 = 1

-1 < 0

1/(m^1) = 1 // * m^1

1 = 1*m^1 // : 1

1 = m^1

m = 1

m in { 1, 1 }

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